COMPUTER SCIENCE PRACTICAL SOLVED QUESTIONS - ISC BOARD 2016
- MARCH 21, 2019
When the leftmost digit is removed and replaced at the end of the remaining string of digits,
the generated number is still prime. The process is repeated until the original number is reached
again.A number is said to be prime if it has only two factors I and itself.
Example:
131
311
113
Hence, 131 is a circular prime.
Test your program with the sample data and some random data:
Example 1:
INPUT :N = 197
OUTPUT:
197
971
719
197 IS A CIRCULAR PRIME
Example 2:
INPUT :N = 1193
OUTPUT:
1193
1931
9311
3119
1193 IS A CIRCULAR PRIME
Example 3:
INPUT : N = 29
OUTPUT:
29
92
29 IS NOT A CIRCULAR PRIME
import java.util.*;
class CircularPrime
{
boolean isPrime(int n) // Function for checking whether a number is prime or not
{
int c = 0;
for(int i = 1; i<=n; i++)
{
if(n%i == 0)
c++;
}
if(c == 2)
return true;
else
return false;
}
int circulate(int n) //Function for circulating the digits to form new number
{
String s = Integer.toString(n);
String p = s.substring(1)+s.charAt(0);
int a = Integer.parseInt(p);
return a;
}
void isCircularPrime(int n) //Function to check for circular prime
{
int f = 0,a = n;
do
{
System.out.println(a);
if(isPrime(a)==false)
{
f = 1;
break;
}
a = circulate(a);
}while(a!=n);
if(f==1)
System.out.println(n+" IS NOT A CIRCULAR PRIME");
else
System.out.println(n+" IS A CIRCULAR PRIME");
}
public static void main(String args[])
{
CircularPrime ob = new CircularPrime();
Scanner sc = new Scanner(System.in);
System.out.print("Enter a number : ");
int n = sc.nextInt();
ob.isCircularPrime(n);
}
}
*****END*************************
Write a program to declare a square matrix A[][] of order (M x M) where ‘M’ must be greater than 3 and less than 10.
Allow the user to input positive integers into this matrix.
Perform the following tasks on the matrix:
(a) Sort the non-boundary elements in ascending order
using any standard sorting technique and rearrange
them in the matrix.
(b) Calculate the sum of both the diagonals.
(c) Display the original matrix, rearranged matrix
and only the diagonal elements of the rearranged
matrix with their sum.
Test your program with the sample data and some random data:
Example 1:
INPUT :M = 4
9 2 1 5
8 13 8 4
15 6 3 11
7 12 23 8
OUTPUT:
ORIGINAL MATRIX
9 2 1 5
8 13 8 4
15 6 3 11
7 12 23 8
REARRANGED MATRIX
9 2 1 5
8 3 6 4
15 8 13 11
7 12 23 8
DIAGONAL ELEMENTS
9 5
3 6
8 13
7 8
SUM OF THE DIAGONAL ELEMENTS = 59
class SortNonBoundary
{
int A[][],B[],m,n;
void input() //Function for taking all the necessary inputs
{
Scanner sc = new Scanner(System.in);
System.out.print("Enter the size of the square matrix : ");
m=sc.nextInt();
if(m<4 || m>10)
{
System.out.println("Invalid Range");
System.exit(0);
}
else
{
A = new int[m][m];
n = (m-2)*(m-2);
B = new int[n]; //Array to store Non-Boundary Elements
System.out.println("Enter the elements of the Matrix : ");
for(int i=0;i<m;i++)
{
for(int j=0;j<m;j++)
{
System.out.print("Enter a value : ");
A[i][j]=sc.nextInt();
}
}
}
}
void convert(int s)
{
int x=0;
for(int i=0;i<m;i++)
{
for(int j=0;j<m;j++)
{
if(i != 0 && j != 0 && i != m-1 && j != m-1)
{
if(s==1)
B[x] = A[i][j];
else
A[i][j] = B[x];
x++;
}
}
}
}
void sortArray() //Function for sorting Non-Boundary
elements stored in array B[]
{
int c = 0;
for(int i=0; i<n-1; i++)
{
for(int j=i+1; j<n; j++)
{
if(B[i]>B[j])
{
c = B[i];
B[i] = B[j];
B[j] = c;
}
}
}
}
void printArray() //Function for printing the array A[][]
{
for(int i=0;i<m;i++)
{
for(int j=0;j<m;j++)
{
System.out.print(A[i][j]+"\t");
}
System.out.println();
}
}
void printDiagonal() //Function for printing the
diagonal elements and their sum
{
int sum = 0;
for(int i=0;i<m;i++)
{
for(int j=0;j<m;j++)
{
if(i==j || (i+j)==m-1)
{
System.out.print(A[i][j]+"\t");
sum = sum + A[i][j];
}
else
System.out.print("\t");
}
System.out.println();
}
System.out.println("Sum of the Diagonal Elements : "+sum);
}
public static void main(String args[])
{
SortNonBoundary = new SortNonBoundary();
ob.input();
System.out.println("*********************");
System.out.println("The original matrix:");
System.out.println("*********************");
ob.printArray(); //Printing the original array
ob.convert(1); //Storing Non-Boundary elements to a 1-D array
ob.sortArray(); //Sorting the 1-D array (i.e. Non-Diagonal Elements)
ob.convert(2); //Storing the sorted Non-Boundary elements back to original 2-D array
System.out.println("*********************");
System.out.println("The Rearranged matrix:");
System.out.println("*********************");
ob.printArray(); //Printing the rearranged array
System.out.println("*********************");
System.out.println("The Diagonal Elements:");
System.out.println("*********************");
ob.printDiagonal(); //Printing the diagonal elements and their sum
}
}
****END**************************
Write a program to accept a sentence which may be terminated by either’.’, ‘?’or’!’ only. The words may be separated by more than one blank space and are in UPPER CASE.
Perform the following tasks:
(a) Find the number of words beginning and ending with a vowel.
(b) Place the words which begin and end with a vowel at the beginning,
followed by the remaining words as they occur in the sentence.
Test your program with the sample data and some random data:
Example 1:
INPUT: ANAMIKA AND SUSAN ARE NEVER GOING TO QUARREL ANYMORE.
OUTPUT: NUMBER OF WORDS BEGINNING AND ENDING WITH A VOWEL= 3
ANAMIKA ARE ANYMORE AND SUSAN NEVER GOING TO QUARREL
Example 2:
INPUT: YOU MUST AIM TO BE A BETTER PERSON TOMORROW THAN YOU ARE TODAY.
OUTPUT: NUMBER OF WORDS BEGINNING AND ENDING WITH A VOWEL= 2
A ARE YOU MUST AIM TO BE BETTER PERSON TOMORROW THAN YOU TODAY
Example 3:
INPUT: LOOK BEFORE YOU LEAP.
OUTPUT: NUMBER OF WORDS BEGINNING AND ENDING WITH A VOWEL= 0
LOOK BEFORE YOU LEAP
Example 4:
INPUT: HOW ARE YOU@
OUTPUT: INVALID INPUT
class SENTENCE
{
boolean isVowel(String w) // Function to check if a word begins and ends with a vowel or not
{
int l = w.length();
char ch1 = w.charAt(0); // Storing the first character
char ch2 = w.charAt(l-1); // Storing the last character
if((ch1=='A' || ch1=='E' || ch1=='I' || ch1=='O' || ch1=='U') &&
(ch2=='A' || ch2=='E' || ch2=='I' || ch2=='O' || ch2=='U'))
{
return true;
}
else
{
return false;
}
}
public static void main(String args[])
{
SENTENCE = new SENTENCE();
Scanner sc = new Scanner(System.in);
System.out.print("Enter a sentence : ");
String s = sc.nextLine();
s = s.toUpperCase();
int l = s.length();
char last = s.charAt(l-1); // Extracting the last character
/* Checking whether the sentence ends with '.' or '?' or not */
if(last != '.' && last != '?' && last != '!')
{
System.out.println("Invalid Input. End a sentence with either '.', '?' or '!' only");
}
else
{
StringTokenizer str = new StringTokenizer(s," .?!");
int x = str.countTokens();
int c = 0;
String w = "", a = "", b = "";
for(int i=1; i<=x; i++)
{
w = str.nextToken(); // Extracting words and saving them in w
if(ob.isVowel(w))
{
c++; // Counting all words beginning and ending with a vowel
a = a + w + " "; // Saving all words beginning and ending with a vowel in variable 'a'
}
else
b = b + w + " "; // Saving all other words in variable 'b'
}
System.out.println("OUTPUT : \nNUMBER OF WORDS BEGINNING AND ENDING WITH A VOWEL = " + c);
System.out.println(a+b);
}
}
}
****END********************
- MARCH 21, 2019
Question 1:
A Circular Prime is a prime number that remains prime under cyclic shifts of its digits.When the leftmost digit is removed and replaced at the end of the remaining string of digits,
the generated number is still prime. The process is repeated until the original number is reached
again.A number is said to be prime if it has only two factors I and itself.
Example:
131
311
113
Hence, 131 is a circular prime.
Test your program with the sample data and some random data:
Example 1:
INPUT :N = 197
OUTPUT:
197
971
719
197 IS A CIRCULAR PRIME
Example 2:
INPUT :N = 1193
OUTPUT:
1193
1931
9311
3119
1193 IS A CIRCULAR PRIME
Example 3:
INPUT : N = 29
OUTPUT:
29
92
29 IS NOT A CIRCULAR PRIME
Solution 3:
import java.util.*;
class CircularPrime
{
boolean isPrime(int n) // Function for checking whether a number is prime or not
{
int c = 0;
for(int i = 1; i<=n; i++)
{
if(n%i == 0)
c++;
}
if(c == 2)
return true;
else
return false;
}
int circulate(int n) //Function for circulating the digits to form new number
{
String s = Integer.toString(n);
String p = s.substring(1)+s.charAt(0);
int a = Integer.parseInt(p);
return a;
}
void isCircularPrime(int n) //Function to check for circular prime
{
int f = 0,a = n;
do
{
System.out.println(a);
if(isPrime(a)==false)
{
f = 1;
break;
}
a = circulate(a);
}while(a!=n);
if(f==1)
System.out.println(n+" IS NOT A CIRCULAR PRIME");
else
System.out.println(n+" IS A CIRCULAR PRIME");
}
public static void main(String args[])
{
CircularPrime ob = new CircularPrime();
Scanner sc = new Scanner(System.in);
System.out.print("Enter a number : ");
int n = sc.nextInt();
ob.isCircularPrime(n);
}
}
*****END*************************
Question 2:
Write a program to declare a square matrix A[][] of order (M x M) where ‘M’ must be greater than 3 and less than 10.
Allow the user to input positive integers into this matrix.
Perform the following tasks on the matrix:
(a) Sort the non-boundary elements in ascending order
using any standard sorting technique and rearrange
them in the matrix.
(b) Calculate the sum of both the diagonals.
(c) Display the original matrix, rearranged matrix
and only the diagonal elements of the rearranged
matrix with their sum.
Test your program with the sample data and some random data:
Example 1:
INPUT :M = 4
9 2 1 5
8 13 8 4
15 6 3 11
7 12 23 8
OUTPUT:
ORIGINAL MATRIX
9 2 1 5
8 13 8 4
15 6 3 11
7 12 23 8
REARRANGED MATRIX
9 2 1 5
8 3 6 4
15 8 13 11
7 12 23 8
DIAGONAL ELEMENTS
9 5
3 6
8 13
7 8
SUM OF THE DIAGONAL ELEMENTS = 59
Solution 2:
import java.util.*;class SortNonBoundary
{
int A[][],B[],m,n;
void input() //Function for taking all the necessary inputs
{
Scanner sc = new Scanner(System.in);
System.out.print("Enter the size of the square matrix : ");
m=sc.nextInt();
if(m<4 || m>10)
{
System.out.println("Invalid Range");
System.exit(0);
}
else
{
A = new int[m][m];
n = (m-2)*(m-2);
B = new int[n]; //Array to store Non-Boundary Elements
System.out.println("Enter the elements of the Matrix : ");
for(int i=0;i<m;i++)
{
for(int j=0;j<m;j++)
{
System.out.print("Enter a value : ");
A[i][j]=sc.nextInt();
}
}
}
}
void convert(int s)
{
int x=0;
for(int i=0;i<m;i++)
{
for(int j=0;j<m;j++)
{
if(i != 0 && j != 0 && i != m-1 && j != m-1)
{
if(s==1)
B[x] = A[i][j];
else
A[i][j] = B[x];
x++;
}
}
}
}
void sortArray() //Function for sorting Non-Boundary
elements stored in array B[]
{
int c = 0;
for(int i=0; i<n-1; i++)
{
for(int j=i+1; j<n; j++)
{
if(B[i]>B[j])
{
c = B[i];
B[i] = B[j];
B[j] = c;
}
}
}
}
void printArray() //Function for printing the array A[][]
{
for(int i=0;i<m;i++)
{
for(int j=0;j<m;j++)
{
System.out.print(A[i][j]+"\t");
}
System.out.println();
}
}
void printDiagonal() //Function for printing the
diagonal elements and their sum
{
int sum = 0;
for(int i=0;i<m;i++)
{
for(int j=0;j<m;j++)
{
if(i==j || (i+j)==m-1)
{
System.out.print(A[i][j]+"\t");
sum = sum + A[i][j];
}
else
System.out.print("\t");
}
System.out.println();
}
System.out.println("Sum of the Diagonal Elements : "+sum);
}
public static void main(String args[])
{
SortNonBoundary = new SortNonBoundary();
ob.input();
System.out.println("*********************");
System.out.println("The original matrix:");
System.out.println("*********************");
ob.printArray(); //Printing the original array
ob.convert(1); //Storing Non-Boundary elements to a 1-D array
ob.sortArray(); //Sorting the 1-D array (i.e. Non-Diagonal Elements)
ob.convert(2); //Storing the sorted Non-Boundary elements back to original 2-D array
System.out.println("*********************");
System.out.println("The Rearranged matrix:");
System.out.println("*********************");
ob.printArray(); //Printing the rearranged array
System.out.println("*********************");
System.out.println("The Diagonal Elements:");
System.out.println("*********************");
ob.printDiagonal(); //Printing the diagonal elements and their sum
}
}
****END**************************
Question 3:
Write a program to accept a sentence which may be terminated by either’.’, ‘?’or’!’ only. The words may be separated by more than one blank space and are in UPPER CASE.
Perform the following tasks:
(a) Find the number of words beginning and ending with a vowel.
(b) Place the words which begin and end with a vowel at the beginning,
followed by the remaining words as they occur in the sentence.
Test your program with the sample data and some random data:
Example 1:
INPUT: ANAMIKA AND SUSAN ARE NEVER GOING TO QUARREL ANYMORE.
OUTPUT: NUMBER OF WORDS BEGINNING AND ENDING WITH A VOWEL= 3
ANAMIKA ARE ANYMORE AND SUSAN NEVER GOING TO QUARREL
Example 2:
INPUT: YOU MUST AIM TO BE A BETTER PERSON TOMORROW THAN YOU ARE TODAY.
OUTPUT: NUMBER OF WORDS BEGINNING AND ENDING WITH A VOWEL= 2
A ARE YOU MUST AIM TO BE BETTER PERSON TOMORROW THAN YOU TODAY
Example 3:
INPUT: LOOK BEFORE YOU LEAP.
OUTPUT: NUMBER OF WORDS BEGINNING AND ENDING WITH A VOWEL= 0
LOOK BEFORE YOU LEAP
Example 4:
INPUT: HOW ARE YOU@
OUTPUT: INVALID INPUT
Solution 3:
import java.util.*;class SENTENCE
{
boolean isVowel(String w) // Function to check if a word begins and ends with a vowel or not
{
int l = w.length();
char ch1 = w.charAt(0); // Storing the first character
char ch2 = w.charAt(l-1); // Storing the last character
if((ch1=='A' || ch1=='E' || ch1=='I' || ch1=='O' || ch1=='U') &&
(ch2=='A' || ch2=='E' || ch2=='I' || ch2=='O' || ch2=='U'))
{
return true;
}
else
{
return false;
}
}
public static void main(String args[])
{
SENTENCE = new SENTENCE();
Scanner sc = new Scanner(System.in);
System.out.print("Enter a sentence : ");
String s = sc.nextLine();
s = s.toUpperCase();
int l = s.length();
char last = s.charAt(l-1); // Extracting the last character
/* Checking whether the sentence ends with '.' or '?' or not */
if(last != '.' && last != '?' && last != '!')
{
System.out.println("Invalid Input. End a sentence with either '.', '?' or '!' only");
}
else
{
StringTokenizer str = new StringTokenizer(s," .?!");
int x = str.countTokens();
int c = 0;
String w = "", a = "", b = "";
for(int i=1; i<=x; i++)
{
w = str.nextToken(); // Extracting words and saving them in w
if(ob.isVowel(w))
{
c++; // Counting all words beginning and ending with a vowel
a = a + w + " "; // Saving all words beginning and ending with a vowel in variable 'a'
}
else
b = b + w + " "; // Saving all other words in variable 'b'
}
System.out.println("OUTPUT : \nNUMBER OF WORDS BEGINNING AND ENDING WITH A VOWEL = " + c);
System.out.println(a+b);
}
}
}
****END********************
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